• mindbleach@sh.itjust.works
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      8 months ago

      JS is a language where [1,2,11].sort() returns [1,11,2].

      And if you use a variable instead of a bare array, half the functions are side-effectful, as determined by coin toss.

      And if you try declaring that variable with new Array(3).map() then it will ignore all 3 indices, because undefined is real enough to be enumerated, but not real enough to be iterated, because, and I cannot overstress the importance of this principle in Javascript, go fuck yourself. Go fuck yourself is why.

    • marcos@lemmy.world
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      8 months ago

      This evaluates to NaN for some reason:

      '10' % 0
      

      Since JS doesn’t really differentiate strings from numbers, except on the places it does, it makes sense to make sure you are working with numbers.

      • FiskFisk33@startrek.website
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        8 months ago

        Oh right that. I guess I was visualizing a scenario where you already checked for it being a number, such as a Number.isInteger(x)

        also, that suprises me a lot, you’d think this is one of the places where it treats stuff as numbers